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#1
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![]() Quote:
I don't think I have time to follow the short method, as it involves determining the GM via experiment, so I'm working through the long method, pg. 174. area mainsail = 140 ft^2 area jib = 164 ft^2 I = 32' wind pressure = 1lb load per lineal foot (mast) = 4.375 lb. Estimating the panels at 17' and 15'. total athwartship load at: masthead = 196.8125 spreader = 266.8125 deck = 304 [code] load * shroud length shroud tension = -------------------- spreader length (estimated 2.5 - 3.0') [/code]upper shroud = (304 * 31.583)/2.5 - 3 = 3840.4928 lbs to 3200.4107 lbs safety/stupidity factor = 4, so roughly 12,800 - 15,200 lbs. load, which by the tables in Skene's suggests stainless 1x19 sized 5/16" to 3/8". This seems a bit heavy, though that may be due to the safety factor (* 2 for error, * 2 for stupidity) |
#2
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![]() I'm trying to work from the Apprentice, pg 136, but the graph of course does not go down to 18.165' waterlines. I'm estimating again, but using a figure of 8,000 for the RM30.
That would give a shroud load of 3,000 lbs. I'm not sure I understood the section regarding selecting wire, mostly the bit in which the load is broken out between uppers and lowers. The cap shrouds by a safety factor of 2.5 would be dealing with a load of 7,500, and the lowers 32.5% of this. Going to the appendix for 1x19 ss 302/304 that suggests 7/32" or 1/4" wire for the cap, 1/8" or 5/32" for the lowers, probably the larger diameter for each. |
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